1.

A system absorbs 520 J of heat and performs work of 210 J. Calculate the change in internal energy.

Answer»

Given : 

Since the heat is absorbed by the system, the work is of expansion. 

Q = 520 J 

W= -210 J 

ΔV = ? 

ΔU = Q + W 

= 520 + (- 210) 

= 310 J

∴ Internal energy change = ΔU = 310 J



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