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A system absorbs 520 J of heat and performs work of 210 J. Calculate the change in internal energy. |
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Answer» Given : Since the heat is absorbed by the system, the work is of expansion. Q = 520 J W= -210 J ΔV = ? ΔU = Q + W = 520 + (- 210) = 310 J ∴ Internal energy change = ΔU = 310 J |
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