A system goes from P to Q by two different paths in the P-V diagram as shown in Fig. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100J. What is the heat exchanged by the system in path 2? Path-1: Heat given= Delta Q_(1) work done by the system Delta W_(1) Path-2 : Heat given = Delta Q_(2) workdone by the system Delta W_(2)

A system goes from P to Q by two different paths in the P-V diagram as

1.	A system goes from P to Q by two different paths in the P-V diagram as shown in Fig. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100J. What is the heat exchanged by the system in path 2? Path-1: Heat given= Delta Q_(1) work done by the system Delta W_(1) Path-2 : Heat given = Delta Q_(2) workdone by the system Delta W_(2)
Answer» <P> SOLUTION :For path 1 `Delta Q_(1) = (U_(Q)-U_(P))+Delta W_(1) :. U_(Q)-U_(P) = Delta Q_(1)-Delta W_(1)` For path 2 `U_(Q)-U_(P)=Delta Q_(2)-Delta W_(2)` `:. Delta Q_(1)-Delta W_(1)=Delta Q_(2)-Delta W_(2)` `Delta Q_(1)-Delta W_(1)+Delta W_(2)=Delta Q_(2)` `Delta Q_(1)-(Delta W_(1)-Delta W_(2))=Delta Q_(2)` `:. 1000-100= Delta Q_(2) "" 900J=Delta Q_(2)`