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A table has mass 5 kg. And its replaced on the floor. If the area of one foot’s table is 5 cm2. find the pressure that apply on it. |
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Answer» Mass of the wooden block, m=5kg Thrust due to wooden block, Mg=5kg×9.8ms −2 =49N (a) SURFACE AREA of 20cm×10cm surface, A=(20×10)cm 2
=(0.2×0.1)m 2
=0.02m 2
P= A mg
P= 0.02m 2
49N
= 0.02 49
Nm −2
or Pressure, P=2450Nm −2 . (b) Surface area of 40cm×20cm surface, A=(40×20)cm 2
=(0.4×0.2)m 2 =0.08m 2
P= 0.08m 2
49N
= 0.08 49
Nm −2
or Pressure, P=612.5Nm −2 . |
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