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A takes 6 days less than the time taken by B to finish a piece of work. If both A and Btogether can finish it in 4 days, find the time that B would take to finish this work byhimself |
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Answer» B alone finish work in x daysA alone work in (x -6) days A one day work = 1/(x-6) B one day work = 1/x A+B one day work = 1/4so, 1/(x-6) + 1/x =1/4x+x-6/x(x-6) = 1/42x-6/x(x-6) =1/44(2x-6) = x(x-6)8x-24 =x^2 - 6xx^2 -14x + 24 = 0x^2 - 12x - 2x + 24 = 0x(x - 12) - 2(x - 12) = 0(x - 2)(x - 12) = 0x = 12 or 2 2 value not possible Therefore, B alone would finish work in 12 days |
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