A tangent to E1:x2+4y2=4 meets E2:x2+2y2=6 at P and Q. Tangents at P a – InterviewSolution

1.	A tangent to E1:x2+4y2=4 meets E2:x2+2y2=6 at P and Q. Tangents at P and Q of E2 make an angle πn (n∈N). Then n2=
Answer» A tangent to $E_{1} : x^{2} + 4 y^{2} = 4$ meets $E_{2} : x^{2} + 2 y^{2} = 6$ at $P$ and $Q$ . Tangents at $P$ and $Q$ of $E_{2}$ make an angle $\frac{π}{n} (n \in N)$ . Then $n^{2} =$

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