Saved Bookmarks
| 1. |
A tangential force 'F' is applied at the topmost point of a spherical shell of mass 'm' kept on a rough horizontal surface. If it rolls without slipping, it's acceleration is (6F)/(xm)" then "'x' |
|
Answer» SOLUTION :`F+f=ma` `FR="f"R=Ia//R` `:.F=(5)/(6)"ma"` `:.a=(6F)/(5M)`
|
|