1.

A tangentialforce of 2100 N is appliedon a surfaceof area 3xx10^(-6)m^(2) which is0.1 m from a fixed face. The force producesa shift of 7 mm of upper surface with respectto bottom. Calculatethe modulusof rigidity of the material.

Answer»

Solution :`F=2100N, A=3XX10^(-6) m^(2)`,
`L=0.1m, DELTAX=7xx10^(-3)m`.
`G=(FL)/( A Deltax)=(2100xx0.1)/(3xx10^(-6)xx7xx10^(-3))=1xx10^(10)NM^(-2)`


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