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A tank can be filled by tap A in 5 hours and tap B in 4 hours. Tap C can empty the filled tank in 8 hours. When the tank is empty, all three taps are opened simultaneously, how long will it take to fill the tank completely?1. \(\frac{10}{3}\) hours2. \(\frac{40}{13}\) hours3. 8 hours4. \(\frac{10}{7}\) hours |
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Answer» Correct Answer - Option 2 : \(\frac{40}{13}\) hours Given: A tank can be filled by tap A in 5 hours, by B in 4 hours, C can empty it in 8 hours Calculation: Efficiency of A = 1/5, of B = 1/4, C = -1/8 Time Taken by A, B, C ∝ 1/Efficiency = (1/5 + 1/4 – 1/8) = (8 + 10 – 5)/40 = 13/40 ∴ Time Taken by A, B, C = 40/13 hours |
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