A tap can fill a tank in 2 hours and by another tap the tank becomes e

1.	A tap can fill a tank in 2 hours and by another tap the tank becomes empty in 3 hours. In how much time will the tank be full when both the taps are open?1. \(1\frac{1}{2}\) hrs.2. \(2\frac{1}{2}\) hrs.3. 4 hrs.4. 6 hrs.
Answer» Correct Answer - Option 4 : 6 hrs. Given: Time taken by the tap-1 to fill the tank = 2 hours Time taken by the tap-2 to empty the tank = 3 hours Calculation: Let the total capacity of tank be 6 units. Part of tank filled in 1 hour by the tap-1 = 6/2 ⇒ 3 units Part of tank emptied in 1 hour by tap-2 = 6/3 ⇒ 2 units Part of tank filled by both the taps together in 1 hour = 3 – 2 ⇒ 1 unit Time taken to fill the full tank = 6/1 = 6 hours ∴ In 6 hours will the tank be full when both the taps are open. We have subtracted the 1 hour work of tap-1 and tap-2 while considering their together work because tap-2 is emptying the tank.

A tap can fill a tank in 2 hours and by another tap the tank becomes empty in 3 hours. In how much time will the tank be full when both the taps are open?1. \(1\frac{1}{2}\) hrs.2. \(2\frac{1}{2}\) hrs.3. 4 hrs.4. 6 hrs.

Answer» Correct Answer - Option 4 : 6 hrs.

Given:

Time taken by the tap-1 to fill the tank = 2 hours

Time taken by the tap-2 to empty the tank = 3 hours

Calculation:

Let the total capacity of tank be 6 units.

Part of tank filled in 1 hour by the tap-1 = 6/2

⇒ 3 units

Part of tank emptied in 1 hour by tap-2 = 6/3

⇒ 2 units

Part of tank filled by both the taps together in 1 hour = 3 – 2

⇒ 1 unit

Time taken to fill the full tank = 6/1 = 6 hours

∴ In 6 hours will the tank be full when both the taps are open.

We have subtracted the 1 hour work of tap-1 and tap-2 while considering their together work because tap-2 is emptying the tank.

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