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A test charge `q_(0)` is moved without acceleration from A to C over the path ABC as shown in Fig. Calcualate potential difference beetween A and C. |
Answer» As is clear from Fig. `vec(AB) + vec(BC) = vec(AC)` As `E = - (dV)/(dr) = (-(V_(C) - V_(A)))/(d) = (V_(A) - V_(C))/(d)` `:. V_(A) - V_(C) =E.d.` |
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