A test tube along with calcium carbonate in it initially weighed 30.08

1.	A test tube along with calcium carbonate in it initially weighed 30.08 g. A heating experiment was performed on this test tube till calcium carbonate completely decomposed with evolution of a gas. Loss of weight during this experiment was 4.40 g. What is the weight of the empty test tube in this experiment?1. 20.08 g 2. 21.00 g 3. 24.50 g 4. 2.008 g
Answer» Correct option: (1) 20.08 g Explanation: CaCO₃ → CaO + CO₂ 1 mole 1 mole 1 mole 100 g 56 g 44 g 4.4 g CO₂ = 0.1 mole According to give data 4.4 g CO₂ will produce along with 5.6 g of CaO due to decomposition of 10 gram of calcium carbonate CaCO₃. Mass of CaCO₃ along with test tube = 30.08 g Mass of CaCO₃ taking in Reaction = 10 g So mass of empty test tube = 30.08 g - 10 g = 20.08 g.

A test tube along with calcium carbonate in it initially weighed 30.08 g. A heating experiment was performed on this test tube till calcium carbonate completely decomposed with evolution of a gas. Loss of weight during this experiment was 4.40 g. What is the weight of the empty test tube in this experiment?1. 20.08 g 2. 21.00 g 3. 24.50 g 4. 2.008 g

Answer»

Correct option: (1) 20.08 g

Explanation:

CaCO₃ → CaO + CO₂

1 mole 1 mole 1 mole

100 g 56 g 44 g

4.4 g CO₂ = 0.1 mole

According to give data 4.4 g CO₂ will produce along with 5.6 g of CaO due to decomposition of 10 gram of calcium carbonate CaCO₃.

Mass of CaCO₃ along with test tube = 30.08 g

Mass of CaCO₃ taking in Reaction = 10 g

So mass of empty test tube = 30.08 g - 10 g = 20.08 g.

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