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A tetravalent element forms monoxide and disoxide wit oxygen. When air is passed over heated element `(1273 K)`. Producer gas is obtained. Monoxide of the lement is a powerful reducing agent and reduces ferric oxide to iron. The element and write formulas of its monoxide and dioxide. Write chemical equations for the formation of producer a gas and reduction if ferric oxide with the monoxide. |
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Answer» Since producer gas is a mixture of CO and `N_(2)`, therefore , the tetravalent element is carbon and its monoxide and dioxide are CO and `CO_(2)` respectively. `2C(s) + ubrace(O_(2)(g)+4N_(2)(g))_("Air") overset(1273K)rarrubrace(2CO(g)+4N_(2)(g))_("Producer gas")` The monoxide of carbon , is a strong reducing agent and reduces ferric oxide to iron. `Fe_(2)O_(3)(s) + 3CO(g) overset(Delta)rarr 2 Fe(s) + 3O_(2)(g)`. |
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