InterviewSolution
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InterviewSolution
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(a) The displacement `s` of a particale in time `t` related as `s = alpha + beta t + gamma t^(2) + delta t^(2)` (b) The veloctiy `v` of particle varies with time as `v = alpha t + beta t^(2) + (gamma )/(t + s)` Findk the dimension fo `alpha, beta, gamma` and `delta`. |
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Answer» (a) Dimensions of each term on the right-hand side have same dimension as that fo `s`, i.e., `[L]` `[alpha] = L` `[beta t] = L implies [beta] = LT^(-1)` `[gamma t^(2)] = L implies [gamma] = LT^(-2)` `[delta t^(2)] = L implies [delta] = LT^(-3)` (b) Dimension of each term on the right-hand side have same dimensions as that of `v`, i.e., `[Lt^(-1)]` `[alphat] = Lt^(-1) implies [alpha] = LT^(-2)` `[beta t^(2)] = LT^(-1) implies [beta] = LT^(-3)` `[delta] = L` `[(gamma)/(t + S)] = LT^(-1) implies [gamma] = L` |
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