1.

A thermodynamic process of one mole ideal monoatomic gas is shown in figure. The efficiency of cyclic process ABCA will be

Answer»

<P>0.25
0.125
0.5
0.077

Solution :`W=(1)/(2)P_(0)V_(0), T_(A)=T_(0),T_(B)=2T_(0),T_(C)=4T_(0)`
Heat supplied =`Q_(AB)+Q_(BC)=C_(V)T_(0)+C_(p)2T_(0)`
`=(13)/(2)RT_(0)=(13)/(2)P_(0)V_(0)`
`therefore` Efficiency of the cyclic process
`((1)/(2) P_(0)V_(0))/((13)/(2)P_(0)V_(0))xx100=(1)/(13)xx100=7.7%`


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