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A thermodynamic study of AlCl_(3(s)) is done to determine its standard enthalpy of formation (Delta_(f)H_(AlCl_(3)(s))^(@)) from the following information. (i) AlCl_(3)(s)s to AlCl_(3) [aq. In 4.0 M-HCl(aq)],DeltaH^(@)=-180 kJ (ii)Al(s)+3HCl (aq.,4.0M) to AlCl_(3) [aq. in 4.0 M-HCl(aq.)]+(3)/(2)H_(2)(g),DeltaH^(@)=-700kJ (iii)(1)/(2) H_(2)(g) +(1)/(2)Cl_(2)(g) to HCl(aq. , 4.0 M), DeltaH^(@)=-158 kJ Determine |Delta_(f)H_(AlCl_(3)(s))^(@)| in kJ from these data: |
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Answer» SOLUTION :[0994] From (ii)+3`XX`(III)-(i),`|DELTAH^(@)|=(-700)+3(-158)-(-180)=+994 kJ//mol` |
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