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InterviewSolution
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A thick wire is stretched so that its length become two times. Assuming that there is no change in its density, then what is the ratio of change in resistance of wire to in initial resistance of wireA. `2 : 1`B. `4 : 1`C. `3 : 1`D. `1 : 4` |
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Answer» Correct Answer - C (c ) In stretching `R prop l^(2) implies (R_(2))/(R_(1)) = (l_(2)^(2))/(l_(1)^(2)) implies (R_(2))/(R_(1)) = ((2)/(1))^(2)` `implies R_(2) = 4 R_(1)`. Change in resistance `= R_(2) - R_(1) = 3R_(1)` Now, `("Changein resistance")/("Original resistance") = (3R_(1))/(R_(1)) = (3)/(1)` |
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