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A thin bulb contains air at normal atmospheric pressure and at 41^(@)C is sealed. The bulb can burst when the air in it is at a temperature of 198^(@)C. Find the pressure of the air at that temperature. |
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Answer» SOLUTION :Initial temperature `t_(1)=41^(@)C , T_(1)=41+273=314K,` Final temperature `t_(2)=198^(@)C` `T_(2)=198+273=471K` Initial PRESSURE `P_(1)=1` atmosphere , Final pressure `P_(2)=?` From CHARLES. law, at constant volume `rArr P_(1)/T_(1)=P_(2)/T_(2)rArr P_(2)=T_(2)/T_(1)P_(1)=471/314 times 1=1.5` atmosphere |
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