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A thin copper ring of radius `a` is charged with `q` units of electricity.An electron is placed at the centre of the copper ring .If the electron is displaced a little, it will have frequencyA. `(1)/(2pi)sqrt((eq)/(4piepsilon_(0)ma^(3)))`B. `(1)/(2pi)sqrt((eq)/(4piepsilon_(0)ema^(3)))`C. `sqrt((eq)/(4piepsilon_(0)ma))`D. `sqrt((q)/(4piepsilon_(0)ema^(3)))` |
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Answer» Correct Answer - 1 Range =`(u^(2)sin^(2)theta)/(2(g+-(EQ)/(m))` |
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