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A thin disc rotates about an axis passing through its centre and perpendicular to its plane a constant angular velocity 'omega' I is the moment of inertia of that disc and'L' is its angular momentum about the given axis. Then rotational kinetic energy of the disc 'E' is (A) EalphaL^(2)"" (B) EalphaL^(-2) (C)EalphaI"" (D) EalphaI^(-1)("if L constant") |
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Answer» A and C are CORRECT |
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