A thin disc rotates about an axis passing through its centre and perpendicular to its plane with a constant angular velocity .omega. I is the moment of inertia of that disc and .L. is its angular momentum about the given axis. Then rotational kinetic energy of the disc .E. is (A) Ealpha L^(2) (B) E alpha E^(-2) (C) E alpha (D) E alpha 1^(-1) (if L constant)

A thin disc rotates about an axis passing through its centre and perpe

1.	A thin disc rotates about an axis passing through its centre and perpendicular to its plane with a constant angular velocity .omega. I is the moment of inertia of that disc and .L. is its angular momentum about the given axis. Then rotational kinetic energy of the disc .E. is (A) Ealpha L^(2) (B) E alpha E^(-2) (C) E alpha (D) E alpha 1^(-1) (if L constant)
Answer» A & C are correct B & C are correct B & D are correct A & D are correct ANSWER :D