Saved Bookmarks
| 1. |
A thin rod of mass m has an angular velocity `omega_(0)` while rotating on a smooth surface. Determine its new angular velocity (in rads//s) just after its end strike and hooks onto the peg and the rod starts to rotate about P without rebounding. Solve the problem using the parameters given. `m=2kg, omega_(0)= rad//s, l=1.5 m` |
|
Answer» Correct Answer - 1 (a) From conservation of angular momentum about P `[(1)/(12)ml^(2)]omega_(0)=[(1)/(3)ml_(2)]omega` `omega= (1)/(4)omega_(0)` (b) From part (a) `omega=(1)/(4)omega_(0)=(1)/(4)(4)=1rad//s` |
|