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A thin rotates about an axis passing through its centre and perpendicular to its plane with a constant angularvelocity .omega. I is the moment of inertia of that discand .L. is its angular momentum about the given axis. Then rotational kinetic energy of the disc .E. is(A) E alpha L^(2)(B) E alpha L^(-2)(C ) E alpha I(D) E alpha I^(-1) (if L constant) |
Answer» <html><body><p>A & <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are correct<br/>B & C are correct<br/>B & D are correct<br/>A & D are correct</p>Answer :D</body></html> | |