1.

A thin wire of mass m and length l is bent in the form of a ring . Moment of inertia of that ring about an axis passing through its centre and perpendicular to its through its centre and perpendicular to its plane isA. `ml^(2)//4pi`B. `ml^(2)//2pi`C. `ml^(2)//4pi^(2)`D. `ml^(2)//2pi^(2)`

Answer» Correct Answer - C
`2pi r = l " " therefore r = (l)/(2 pi)`
`I = mr^(2)`
`= (ml^(2))/(4pi^(2))`. `I = mr^(2)`
`= (ml^(2))/(4pi^(2))`.


Discussion

No Comment Found

Related InterviewSolutions