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(a) Three resistors `1 Omega, 2Omega and 3 Omega` are combined in series. What is the total resistance of the combination ? (b) If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor. |
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Answer» (a) Here, `R_(1) = 1 Omega , R_(2)2 Omega , R_(3) = 3 Omega , V = 12 V` `{:(,"In series, total resistance",,R_(S)=R_(1)+R_(2)+R_(3)=1+2+3=6 Omega),((b),"Current through the circuit",,I = V//R_(s)=12//6=2A),( :.,"Potential drop across",,R_(1)=I R_(1)=2xx1 =2V),(,"Potential drop across",,R_(2)=I R_(2)=2xx2=4V),(,"Potential drop across",,R_(3)=IR_(3)=2xx3=6V),(,,,):}` |
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