Saved Bookmarks
| 1. |
A time dependent force F = 6t acts on a particle of mass 1 kg . If the particle starts from rest , the work done by the force during the first 1 sec , will be ………. |
|
Answer» 9 J ` :. "ma = 6t` ` :. A = (6t)/m = (6t)/m = 1 = 6t` ` :. (dv)/(DT) = 6t` ` :."dv = 6t dt"` ` :. Int_(0)^(v) dv - 6 int_(0)^(1) " t dt "` ` = 6 xx1/2[ :. t = 1 ] ` = 3 m/s ` W = 1/2 MV^(2) - 1/2 mv_(0)^(2)` ` = 1/2 xx1xx9-0` `= 4.5 J ` |
|