1.

A time dependent force F = 6t acts on a particle of mass 1 kg . If the particle starts from rest , the work done by the force during the first 1 sec , will be ……….

Answer»

9 J
18 J
`4.5` J
22 J

Solution :F = 6t
` :. "ma = 6t`
` :. A = (6t)/m = (6t)/m = 1 = 6t`
` :. (dv)/(DT) = 6t`
` :."dv = 6t dt"`
` :. Int_(0)^(v) dv - 6 int_(0)^(1) " t dt "`
` = 6 xx1/2[ :. t = 1 ] `
= 3 m/s
` W = 1/2 MV^(2) - 1/2 mv_(0)^(2)`
` = 1/2 xx1xx9-0`
`= 4.5 J `


Discussion

No Comment Found