A time varying force, `F=2t` is acting on a particle of mass `2kg` moving along x-axis. velocity of the particle is `4m//s` along negative x-axis at time `t=0`. Find the velocity of the particle at the end of 4s.

A time varying force, `F=2t` is acting on a particle of mass `2kg` mov

1.	A time varying force, `F=2t` is acting on a particle of mass `2kg` moving along x-axis. velocity of the particle is `4m//s` along negative x-axis at time `t=0`. Find the velocity of the particle at the end of 4s.
Answer» Correct Answer - D Given force is a funciton of time. So, linear impulse can be obtained by integration. Further, this impulse is equal to change in linear momentum. Thus, `J=intFdt=Deltap=p_f-p_i=m(v_f-v_i)` or `v_f=1/mintFdt+v_i=1/2int_0^4(2t)dt-4` `(v_i=-4m//s)` `=1/2[t^2]_10^4-4=1/2[16-0]-4` `=+4m//s` Therefore, the final velocity is `4m//s` along positive x-direction.

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A time varying force, `F=2t` is acting on a particle of mass `2kg` moving along x-axis. velocity of the particle is `4m//s` along negative x-axis at time `t=0`. Find the velocity of the particle at the end of 4s.

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