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A tin had ‘x’ litre oil. Another tin had (3x2 + 6x – 5) litre of oil. The shopkeeper added (x + 7) litre more to the second tin. Later he sold (x2 + 6) litres of oil from the second tin. How much oil was left In the second tin? |
Answer» Quantity of oil in the second tin = 3x2 + 6x – 5 litres. Quantity of oil added = x + 7 litres ∴ Total quantity of oil in the second tin = (3x2 + 6x – 5) + (x + 7) litres = 3x2 + (6x + x) + (-5 + 7) = 3x2 + (6 + 1)x + 2 = 3x2 + 7x + 2 litres Quantity of oil sold = x + 6 litres ∴ Quantity of oil left in the second tin = (3x2 + 7x + 2) – (x2 + 6)(3x2 – x2 ) + 7x + (2 – 6) = (3 – 1)x2 + 7x + (-4) = 2x2 + 7x – 4 Quantity of oil left = 2x2 + 7x – 4 litres |
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