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A tiny electric dipole of dipole moment `vecP = P_0hatj` is placed at point (l,0). There exists an electric field `vecE = 2ax^2hati + (2by^2 + 2cy)hatj`.A. Force on dipole is `2P_0ahati`.B. Force on dipole is `2P_0bhati`.C. Force on dipole is `2P_0chatj`.D. Force on dipole is `-2P_0chatj`. |
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Answer» Correct Answer - C c. `Fx=Px(delE_(x))/(delX)=0` `F_(Y)=P_(Y)=(delE_(Y))/(del_(Y))=P_(0)(4by+2c)` `therefore F=2cP_(0)hatj` |
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