InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A toroid has a core (non ferromagnetic material) of inner radius `25cm` and outer radius `26cm` around which 3500 turns of wire are wound. If the current in the wire is `11A`, what is the magnetic field (a) outside the toroid (b) inside the core of the toroid (c) in the empty space surrounded by the toroid? |
|
Answer» Here, `r_1=0*25m`, `r_2=0*26m`, `N=3500`, `I=11A` (i) Outside the toroid, the magnetic field is zero. (ii) Inside the core of the toroid, the magnetic field induction is, `B=mu_0nI`, where n is the number of turns per unit length of toroid `=N//l`. Here, mean length of toroid, `l=2pi((r_1+r_2)/(2))=pi(r_1+r_2)=pi(0*25+0*26)=pixx0*51m` So `B=(mu_0NI)/(l)=((4pixx10^-7)xx3500xx11)/(pixx0*51)=3*02xx10^-2T` (iii) In the empty space surrounded by toroid, the magnetic field is zero. |
|