A torque of 10 Nm is applied to a flywheel of mass 10 kg and radius of gyration 50 cm. What is the resultant angular acceleration ?

A torque of 10 Nm is applied to a flywheel of mass 10 kg and radius of

1.	A torque of 10 Nm is applied to a flywheel of mass 10 kg and radius of gyration 50 cm. What is the resultant angular acceleration ?
Answer» Solution :`rau = 10 N, I = MK^(2)=10 xx 0.5^(2) = 2.5 kgm^(2), ALPHA = tau//l = 10//2.5 = 4 "rads"^(-2)`