

InterviewSolution
Saved Bookmarks
1. |
A torque of `2X10^(-4)Nm` is required to hold a magnet at right angle to the magnetic meridian. The torque required to hold it at `30^(@)` to the magnetic meridian in `N-m` isA. `0.5xx10^(-4)`B. `1xx10^(-4)`C. `4xx10^(-4)`D. `8xx10^(-4)` |
Answer» Correct Answer - B `C=MB_(H)sintheta` |
|