Saved Bookmarks
| 1. |
A tosses `2` fair coins & `B` tosses 3 fair cons after game is won by the person who throws greater number of heads. In case of a tie, the game is continued under identical rules until someone finally wins the game. The probability that A finally wins the game is `K//11`, then `K` is |
|
Answer» Correct Answer - 3 `A_(i)=` no. of heads obtained by `A` when tosses two coins `B_(i)=` no of heads obtained by `B` when tosses `3` coins `P(E)=P{(A_(1)nnB_(0))uu(A_(2)nnB_(2))uu(A_(2)nnB_(1))}` `=2C_(1)(1/2)(1/2)(1/2)^(3)+(1/2)^(2)+(1/2)^(2)3C_(1)(1/2)(1/2)^(2)` `=2/32+1/32+3/32=3/36` `F={A` & `B` tie a particular game `}` then`P(F)=P{(A_(0)nnB_(0))uu(A_(1)nnB_(1))uu(A_(2)nnB_(2))}=5/16` `P` (`A` finally wins the game ) `=P(E` or `FE` or `FFE` or ........) `=3/11` |
|