A toy cyclist completes one round of a square track of side 2 min 40 seconds. What will be the displacement at theend of 3 minutes?

A toy cyclist completes one round of a square track of side 2 min 40 s

1.	A toy cyclist completes one round of a square track of side 2 min 40 seconds. What will be the displacement at theend of 3 minutes?
Answer» 52 m zero 16 m `2sqrt2m` Solution :TOTAL TIME of motion on square track `= 3 min = 3 xx 60 = 180 s` Time period of revolution= 40 s `:.` Displacement in160 s `(=4xx 40) = 0 `, as toy CYCLIST will be reaching at the straight point . Thus displacement in 18 s displacement in 20 s `=sqrt((20)^2+(2)^2)=2sqrt2` m