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a train accelerated from 36 kilometre per hour in 10 seconds . 1.find acceleration .2 the distance travelled by car |
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Answer» tion:Given:INITIAL velocity= 36km/h=36x5/18=10m/sFinal velocity =54km/h=54x5/18=15m/sTime =10secAcceleration = v-u/ t=15-10/10=5/10=1/2=0.5 m/s2Distance =s=?From second EQUATION of motion:S=ut +1/2 at^2=10*10+1/2*0.5*10*10=100+25=125mSo distance TRAVELLED is 125myou can PUT the CORRECT number |
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