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A train is moving southwards with a speed of 30ms-1. A man is running on the roof of the train with speed of 5ms-1 with respect to the train. Find the velocity of the man as observed by the person on the ground if the man is running1. southwards2. northwards. |
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Answer» If vA and vB are the velocity of the two bodies moving along the same direction with respect to the ground, relative velocity of A with respect to B is given by, VAB = VA – VB …………. (1) Here, the velocity of the man with respect to the train, vAB = 5ms-1 velocity of the train with respect to the ground is, vB = 30 ms-1 ∴ velocity of the man with respect to the ground, vA = vB + vAB = 30 + 5 = 35 ms-1 if the man moves southwards. On the other hand, if the man moves northwards, vAB = – 5 ms-1 ∴ VA = VB – VAB = 25 ms-1 |
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