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A train is moving with a unifrom speed of 33 m/ s and an observer is approaching the train with the same speed. If the train blows a whistle of frequency 1000 Hz and the velocity of sound is 333 m/s, then the apparent frequency of the sound that the observer hear is |
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Answer» 1220 Hz Velocity of the observer, `u_(0)=33 m//s)` Now, velocity of sound, V = 333 m/s As the source and the observer are approching each other, so , APPARENT frequency, `n.=(v+u_(0))/(v-u_(2)) cdot n =(333+33)/(333-333)xx1000 = 1220 ` HzThe option (A) is correct. |
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