1.

A train is moving with constant acceleration. When the ends of the train pass by a signal their speeds are 30 km/h and 40 km/h respectively. Calculate the speed of the midpoint of train while passing the signal.

Answer»

35 km/hr
`(25)/(sqrt2) km//hr`
`25 sqrt2 km//hr`
`25 km//hr`

Solution :Velocity of midpoint is
`V. = SQRT (( u ^(2) + v ^(2))/( 2 )) = sqrt (((30 ) ^(2) + (40 ^(2))^(2))/( 2))`
`therefore v. = sqrt (( 900+ 1600)/(2)) = sqrt ((2500)/(2))`
`therefore v. = (50)/(sqrt2) = 25 sqrt2 (m)/(s)`


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