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A train is travelling at a speed of 90 km per hour.Brakes are applied so as to produce a uniform acceleration of -0.5 metre per second square. Find how far the train will go before it is brought to rest. Please urgent​

Answer»

answer is 625m Explanation:firstly find TIME taken to STOP the car by identity V=u +at            u = 90 × 5/18      ( converting into m/s)               = 25m/s             a = -0.5 m/s^2             v = 0m/s   0 = 25 - 0.5 t  t = 50S now find distance by  s = ut + 1/2 at^2     s = 25 × 50 - 1/2 × 0.5 ×50 ×50     s = 625m



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