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A train is travelling at a speed of 90 km per hour.Brakes are applied so as to produce a uniform acceleration of -0.5 metre per second square. Find how far the train will go before it is brought to rest. Please urgent |
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Answer» answer is 625m Explanation:firstly find TIME taken to STOP the car by identity V=u +at u = 90 × 5/18 ( converting into m/s) = 25m/s a = -0.5 m/s^2 v = 0m/s 0 = 25 - 0.5 t t = 50S now find distance by s = ut + 1/2 at^2 s = 25 × 50 - 1/2 × 0.5 ×50 ×50 s = 625m |
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