InterviewSolution
Saved Bookmarks
| 1. |
A Train Moves Fast A Telegraph Post And A Bridge 264 M Long In 8 Sec And 20 Sec Respectively. What Is The Speed Of The Train? |
|
Answer» Let the LENGTH of the train be x m and its speed be y m/sec. Then, x/y = 8 => x = 8Y (x + 264)/20 = y y = 22 Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr. Let the length of the train be x m and its speed be y m/sec. Then, x/y = 8 => x = 8y (x + 264)/20 = y y = 22 Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr. |
|