1.

A Train Moves Fast A Telegraph Post And A Bridge 264 M Long In 8 Sec And 20 Sec Respectively. What Is The Speed Of The Train?

Answer»

Let the LENGTH of the train be x m and its speed be y m/sec.

Then, x/y = 8 => x = 8Y

(x + 264)/20 = y

y = 22

Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.

Let the length of the train be x m and its speed be y m/sec.

Then, x/y = 8 => x = 8y

(x + 264)/20 = y

y = 22

Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.



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