1.

A Train Moves Past A Telegraph Post And A Bridge 264 M Long In 8 Seconds And 20 Seconds Respectively. What Is The Speed Of The Train?

Answer»

Let the length of the train be x meters and its SPEED by y m/sec.

Then, x/y = 8 => x = 8y ----------- (1)

As per the question total distance = (x + 264) meters.

(x + 264)/20 = y

Put the value of x from equation 1. 

=> 8y + 264 = 20y

=> y = 22.

Therefore Speed = 22 m/sec = ( 22 x 18 /5) km/hr = 79.2 km/hr.

Let the length of the train be x meters and its speed by y m/sec.

Then, x/y = 8 => x = 8y ----------- (1)

As per the question total distance = (x + 264) meters.

(x + 264)/20 = y

Put the value of x from equation 1. 

=> 8y + 264 = 20y

=> y = 22.

Therefore Speed = 22 m/sec = ( 22 x 18 /5) km/hr = 79.2 km/hr.



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