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A Train Moves Past A Telegraph Post And A Bridge 264 M Long In 8 Seconds And 20 Seconds Respectively. What Is The Speed Of The Train? |
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Answer» Let the length of the train be x meters and its SPEED by y m/sec. Then, x/y = 8 => x = 8y ----------- (1) As per the question total distance = (x + 264) meters. (x + 264)/20 = y Put the value of x from equation 1. => 8y + 264 = 20y => y = 22. Therefore Speed = 22 m/sec = ( 22 x 18 /5) km/hr = 79.2 km/hr. Let the length of the train be x meters and its speed by y m/sec. Then, x/y = 8 => x = 8y ----------- (1) As per the question total distance = (x + 264) meters. (x + 264)/20 = y Put the value of x from equation 1. => 8y + 264 = 20y => y = 22. Therefore Speed = 22 m/sec = ( 22 x 18 /5) km/hr = 79.2 km/hr. |
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