A train of 100 m length moves with 40 m/s and overtakes another train of 200 m length moves with 30 ms^(-1). Time taken by 1^(st) train to overtake another train is ......

A train of 100 m length moves with 40 m/s and overtakes another train

1.	A train of 100 m length moves with 40 m/s and overtakes another train of 200 m length moves with 30 ms^(-1). Time taken by 1^(st) train to overtake another train is ......
Answer» 30 s 40 s 50 s 60 s Solution :RELATIVE velocity `= 40 - 30 = 10 ms ^(-1)` Distance covered before overtake `= 100 + 200 = 300 m` `therefore ` TIME taken to overtake `= ("distance")/("relative velocity") = (300)/(10)=30s`