A train of mass 10,000 kg moving at 72km ph rounds a curve whose radiu

1.	A train of mass 10,000 kg moving at 72km ph rounds a curve whose radius of curvature is 200m. What is its acceleration? What is the centripetal force?
Answer» m = 10,000kg, v = 72 km/h = \(\frac {72 \times 1000}{60 \times 60} = 20 m/s\) r = 200 m. Acceleration a = v ω = \(v\frac{v}{\tau}\) = \(\frac {v^2}{\tau} = \frac {(20)}{200}\) = 2m/s² Centripetal force, F = \(\frac {mv^2}{\tau}\) \(\frac {10000 \times(20)^2}{200}\) = 20000 N.

A train of mass 10,000 kg moving at 72km ph rounds a curve whose radius of curvature is 200m. What is its acceleration? What is the centripetal force?

Answer»

m = 10,000kg, v = 72 km/h

= \(\frac {72 \times 1000}{60 \times 60} = 20 m/s\)

r = 200 m.

Acceleration a = v ω

= \(v\frac{v}{\tau}\)

= \(\frac {v^2}{\tau} = \frac {(20)}{200}\)

= 2m/s²

Centripetal force, F = \(\frac {mv^2}{\tau}\)

\(\frac {10000 \times(20)^2}{200}\)

= 20000 N.