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A train of some length travelling at the speed of 108 km per hour can cross a pole on a platform in 25 seconds but at the speed of 90 km per hour it can cross a platform of x meters long in 40 seconds. Quantity I: What is the length of the train? Quantity II: What is the length of the platform?1. Quantity 1 > Quantity 22. Quantity 1 ≥ Quantity 23. Quantity 1 < Quantity 24. Quantity 1 ≤ Quantity 25. Quantity 1 = Quantity 2 |
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Answer» Correct Answer - Option 1 : Quantity 1 > Quantity 2 Given: Speed of train = 108 km/hr Time to cross pole = 25s At 90 km/hr time taken to cross platform of x meters = 40 seconds Calculation: 108 km/hr = 30 m/s (∵ 108 × 5 / 18 = 30) Quantity I: The length of the train = 30 × 25 = 750 meters Quantity II: 90 km/hr = 25 m/s Let the length of the platform = x meters ⇒ (750 + x) = 25 × 40 ⇒ 1000 m ⇒ x = 1000 – 750 ⇒ x = 250 meters ∴ Quantity I > Quantity II |
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