A train of weight 10^7 N is running on a level track with uniform speed of 36 km h^(-1). The frictional force is 0.5 kg f per quintal. If g = 10 ms^(-2), power of engine is

A train of weight 10^7 N is running on a level track with uniform spee

1.	A train of weight 10^7 N is running on a level track with uniform speed of 36 km h^(-1). The frictional force is 0.5 kg f per quintal. If g = 10 ms^(-2), power of engine is
Answer» <P>500 kW 50 kW 5 kW 0.5 kW Solution :Weight of train = `10^(7) N = 10^6 kg f` Frictional force, `f = (0.5)/(100) xx 10^(6) = 5000 kg, N= 50000 N` `v = 36 km H^(-1) = 10 ms^(-1)` The power of engine is `P = f xx v = 50000 xx 10 = 5 xx 10^(5) W = 500 k W ` .