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A train starting from a railway station and moving with uniform acceleration attains a speed of 40 km ^(-1) in 10 minute. Find its acceleration. |
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Answer» `1ms ^(-2)` `16= v _(0) + 8a ""…(1)` Now, `d = 9M, t =3s` `9= 3v_(0) + (9a)/(2) THEREFORE 18 = 6v_(0) + 9a ""…(2)` `therefore 48=12v_(0) + 24 a ` (eq. (i) is multiplied by 3) `36=12v _(0) + 18 a ` (eq. (ii) is multiplied by 2) `{:(-,-,-), (12=6a,,),(therefore a = 2ms ^(-2),,):}` |
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