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A train starting from a railway station and moving with uniform acceleration attains a speed `40 km//h` in `10` minutes. Find its acceleration. |
Answer» Here,`" "` Initial speed of train, `u= 0 " "` (Starts from rest) Final speed of train, `v= 40 ` km `h^(-1)` `" "= (40xx100" m")/(60xx60" s")` `" "= 11.11" m" s^(-1)` And, `" "`Time taken, `t` = 10 minutes `" "=10xx60` seconds `" "= 600` s Now, `" "` Acceleration, `a=(v-u)/(t)` `" "a= (11.11-0)/(600)` `" "a=(11.11)/(600)" m" s^(-2)` ltBrgt `" "a= 0.0185" m "s^(-2)" "(or 1.85xx10^(-2)" m" s^(-2))` |
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