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A train starting from rest attained a velocity of30m/s in 30 minutes. What is the acceleration ? |
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Answer» as u=0v=atv=30 m/s=30 x60=1800 m/minso a=v/t=1800/30=60 m/min sqr Given :Initial Velocity = u = 0m/sFinal velocity= V= 30 km/hTime = 30 min =1/2 h\xa0acceleration=a=?As we know that , a=v-u/t⇒a=30 - 0/1/2=30× 2= 60 km/h² |
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