A train starts to move from rest. If the velocity of the train is 90 km/hr in 2 minutes and 30 seconds, then What is the acceleration? What distance does the train travel?

A train starts to move from rest. If the velocity of the train is 90 k

1.	A train starts to move from rest. If the velocity of the train is 90 km/hr in 2 minutes and 30 seconds, then What is the acceleration? What distance does the train travel?
Answer» TION:Given that,Acceleration a=−0.5m/s 2 SPEED v=90km/h=25m/sUsing equation of motion, v=u+atWhere, v = final velocityu = initial velocitya = accelerationt = timePut the value into the equationFinally train will be rest so, final VELOCITY,v=00=25−0.5t25=0.5tt= 0.525 t=50 secAgain, using equation of motion, S=ut+ 21 at 2 Where, s = distancev = final velocityu = initial velocitya = accelerationt = timePut the value into the equationWhere S is distance travelled before stops=25×50− 21 ×0.5×(50) 2 s=625 mSo, the train will go before it is brought to rest is 625 m.Please mark me brainliest!!