A train traveling along a straight track with a speed of 2 ms-1, begin

1.	A train traveling along a straight track with a speed of 2 ms-1, begins to accelerate with a=2/v ms^-2where v is in ms-1. Find its velocity after 3 seconds in m/s.
Answer» Answer: 8ms-1 Explanation: The acceleration of an object can be calculated by the FORMULAR A=(vf-vi)/Tf-Ti) Where A =Acceleration Vf=Final VELOCITY Vi= Initial velocity Ti=Initial Time Tf =Final Time In this case, A=2/V MS -2 Vi=2ms-1 Ti-Tf we are given as 3 SECONDS Therefore to find Vf after three seconds, We assume that; Vf= X Replacing Vf in the formular 2=(x-2ms-1)/3 6=x-2 x=8 Replacing x with Vf Vf=8

A train traveling along a straight track with a speed of 2 ms-1, begins to accelerate with a=2/v ms^-2where v is in ms-1. Find its velocity after 3 seconds in m/s.

Answer»

Answer:

8ms-1

Explanation:

The acceleration of an object can be calculated by the FORMULAR

A=(vf-vi)/Tf-Ti)

Where A =Acceleration

Vf=Final VELOCITY

Vi= Initial velocity

Ti=Initial Time

Tf =Final Time

In this case,

A=2/V MS -2

Vi=2ms-1

Ti-Tf we are given as 3 SECONDS

Therefore to find Vf after three seconds, We assume that;

Vf= X

Replacing Vf in the formular

2=(x-2ms-1)/3

6=x-2

x=8

Replacing x with Vf

Vf=8

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A train traveling along a straight track with a speed of 2 ms-1, begins to accelerate with a=2/v ms^-2where v is in ms-1. Find its velocity after 3 seconds in m/s.​

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A train traveling along a straight track with a speed of 2 ms-1, begins to accelerate with a=2/v ms^-2where v is in ms-1. Find its velocity after 3 seconds in m/s.