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A train travelling at a speed of 90 kmph. Brakes are applied so as to produce a uniform acceleration of ‒0.5 ms-2. Find how far the train will go before it is brought to rest?

Answer» 625 mExplanation:90 KMPH = 90*5/18 = 25 m/sv²=u²+2as ⇒ 0 = (25)²-2*(0.5)(s)⇒ s = 625 m


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